veera pi mapping udf 22nd april 2026
again udpate code; as per this logic: 1) var1 ---any one is value then outputValue true else 2) var1---- all emppty--- and var2 or var3 ---any contains CTH then outputValue true else 3) var1---- all emppty--- and var2 or var3 ---no CTH then outputValue false --- ------------- //inside udf; // Step 1: Check conditions on var1 boolean anyVar1HasValue = false; boolean allVar1Empty = true; for (int i = 0; i < var1.length; i++) { boolean isEmpty = (var1[i] == null || var1[i].trim().isEmpty()); anyVar1HasValue = anyVar1HasValue || !isEmpty; allVar1Empty = allVar1Empty && isEmpty; } // Step 2: Check if ANY entry in var2 or var3 contains "CTH" boolean anyCTHFound = false; for (int i = 0; i < var2.length; i++) { boolean containsCTH = (var2[i] != null && var2[i].contains("CTH")); anyCTHFound = anyCTHFound || containsCTH; } for (int i = 0; i < var3....