veera pi mapping udf 22nd april 2026

 again udpate code; as per this logic:

 1) var1 ---any one is value then outputValue true 

 else 

2) var1---- all emppty--- and var2 or var3 ---any contains CTH then outputValue true 

 else 

 3) var1---- all emppty--- and var2 or var3 ---no CTH then outputValue false

---

-------------

//inside udf;

// Step 1: Check conditions on var1

boolean anyVar1HasValue = false;

boolean allVar1Empty = true;

for (int i = 0; i < var1.length; i++) {

    boolean isEmpty = (var1[i] == null || var1[i].trim().isEmpty());

    anyVar1HasValue = anyVar1HasValue || !isEmpty;

    allVar1Empty = allVar1Empty && isEmpty;

}

// Step 2: Check if ANY entry in var2 or var3 contains "CTH"

boolean anyCTHFound = false;

for (int i = 0; i < var2.length; i++) {

    boolean containsCTH = (var2[i] != null && var2[i].contains("CTH"));

    anyCTHFound = anyCTHFound || containsCTH;

}

for (int i = 0; i < var3.length; i++) {

    boolean containsCTH = (var3[i] != null && var3[i].contains("CTH"));

    anyCTHFound = anyCTHFound || containsCTH;

}

// Step 3: Apply priority logic

String outputValue = "false";

if (anyVar1HasValue) {

    outputValue = "true";

} else if (allVar1Empty && anyCTHFound) {

    outputValue = "true";

} else {

    outputValue = "false";

}

// Step 4: Assign result for all occurrences

for (int i = 0; i < var1.length; i++) {

    result.addValue(outputValue);

}